函数fx=(x 1)²(x-1)³的极大值点
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函数fx=(x 1)²(x-1)³的极大值点
函数fx=(x 1)²(x-1)³的极大值点
函数fx=(x 1)²(x-1)³的极大值点
f'=2(x+1)(x-1)³-3(x+1)²(x-1)²=0
(x+1)(x-1)²(2x-2-3x-3)=0
f'=-(x+5)(x+1)(x-1)²=0
(x+1)(x-1)²(x+5)=0
x=-1,x=1或x=-5
x<-5时,f'<0
-5
所以
x=-5是极大值点;
-1
x>1
f'<0
x=1不是极值点
所以
极大值点为x=-5.