-(-2y+1)-(5-4y)-(+5)其中y=-2
来源:学生作业帮助网 编辑:作业帮 时间:2024/12/01 19:01:28
x)5605RڦO[=ٱV&H;y7~[J]C]SmJ]SP54BmV9@ť
V] ɗU
-(-2y+1)-(5-4y)-(+5)其中y=-2
-(-2y+1)-(5-4y)-(+5)其中y=-2
-(-2y+1)-(5-4y)-(+5)其中y=-2
原式=2y-1-5+4y-5
=6y-11
=-12-11
=-23
原式=2y-1-5+4y-5=6y-11=-12-11=-23
2y-1-5+4y-5
=-4-1-5-8-5
=-23
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
1/2y+1=4y-2/5-y
计算:[(y+1)/(y^2-4y+3)减去(y-2)/(y^2-6y+9)]除以(y-5)/(y-1)
y-1/y-2 - y-3/y-4=y-2/y-3 - y-4/y-5一共有四个分数哦~希望可以快一点~谢谢!
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
解3y+5/3y-6=1/2+5y-4/2y-4
4(2y+5)-3y=7(y-5)+4(2y+1)
4(5—2y)+7(y+1)=3(4y-1)+17求y
4*(5—2y)+7(y+1)=3(4y-1)+17求y
若 4y^2-2y+5=7 则 2y^2-y+1=?
代数式4y² - 2y + 5 = 7,那么代数式2y² - y + 1
计算:(-3y)^2(2y+1)-(3y-5)(3y+4)
计算(3y-1)(2y+3)-(6y-5)(y-4)
(3y-1)(2y-3)+(6y-5)(y-4)=?xie
(3y-1)(2y一3)十(6y一5)(y一4)
(3y-1)(2y-3)+(6y+5)(y-4)=?