求(sin^6α+cos^6α)/(sin^4α+cos^4α)的值

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求(sin^6α+cos^6α)/(sin^4α+cos^4α)的值
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求(sin^6α+cos^6α)/(sin^4α+cos^4α)的值
求(sin^6α+cos^6α)/(sin^4α+cos^4α)的值

求(sin^6α+cos^6α)/(sin^4α+cos^4α)的值
分子=(sinx)^6+(cosx)^6=(sin²x)³+(cos²x)³=(sin²x+cos²x)[(sinx)^4-sin²xcos²x+(cosx)^4]=(sin²x+cos²x)²-3sin²xcos²x=1-3(sinxcosx)².分母=(sin²x+cos²x)²-2(sinxcosx)²=1-2(sinxcosx)².∴原式=[1-3(sinxcosx)²]/[1-2(sinxcosx)²].只能这样了,求不出值的.请再看看题.

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