(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
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(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2)
请问这是怎么变形的?
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2) 请问这是怎么变形的?
提取公因式(x1-x2)
(x1-x2)+(x2-X1)/x1x2=(x1-x2)-(x1-x2)/x1x2,提取公因式(x1-x2)得出(x1-x2)(1-1/x1x2)
(x1-x2)-(x1-x2)/x1x2 = (x1-x2)(1- 1/x1x2)
1 - 1/x1x2 = 1-1/x1x2
x1-x2)+x1x2分之4(x2-x1)怎样化简成((x1-x2)(1-x1x2分之4)
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