已知函数f(x)=(x+1)Inx-x+1.(1)若xf'(x)≤x^2+ax+1,求a的取值范围;(2)证明:(x-1)f(x)≥0.已知函数f(x)=(x+1)Inx-x+1.(1)若xf'(x)≤x^2+ax+1,求a的取值范围;(2)证明:(x-1)f(x)≥0.
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![已知函数f(x)=(x+1)Inx-x+1.(1)若xf'(x)≤x^2+ax+1,求a的取值范围;(2)证明:(x-1)f(x)≥0.已知函数f(x)=(x+1)Inx-x+1.(1)若xf'(x)≤x^2+ax+1,求a的取值范围;(2)证明:(x-1)f(x)≥0.](/uploads/image/z/2523331-19-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D%28x%2B1%29Inx-x%2B1.%281%29%E8%8B%A5xf%27%28x%29%E2%89%A4x%5E2%2Bax%2B1%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%3B%282%29%E8%AF%81%E6%98%8E%3A%28x-1%29f%28x%29%E2%89%A50.%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3D%28x%2B1%29Inx-x%2B1.%281%29%E8%8B%A5xf%27%28x%29%E2%89%A4x%5E2%2Bax%2B1%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%3B%282%29%E8%AF%81%E6%98%8E%3A%28x-1%29f%28x%29%E2%89%A50.)
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