圆x²+y²-4x+4y+6=0 截直线 x-y-5=0所得的弦长=
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圆x²+y²-4x+4y+6=0 截直线 x-y-5=0所得的弦长=
圆x²+y²-4x+4y+6=0 截直线 x-y-5=0所得的弦长=
圆x²+y²-4x+4y+6=0 截直线 x-y-5=0所得的弦长=
即(x-2)²+(y+2)²=2
圆心C(2,-2),r=√2
C到弦的距离d=|2+2-5|/√(1²+1²)=√2/2
所以弦长=2√(r²-d²)=√3