S=1²-2²+3²-4²……+99²-100²+101²,求S被103除的余数
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S=1²-2²+3²-4²……+99²-100²+101²,求S被103除的余数
S=1²-2²+3²-4²……+99²-100²+101²,求S被103除的余数
S=1²-2²+3²-4²……+99²-100²+101²,求S被103除的余数
S=1²-2²+3²-4²……+99²-100²+101²,
=(1+2)(1-2)+(3+4)(3-4)+...+(99+100)(99-100)+101²
=-1-2-3-4..-99-100+101²
=-(1+100)x100/2+101²
=101²-50x101
=51x101
=5151
5151÷103=50余1
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