(3x^2-2x+1)^2-(3x^2-2x-5)^25/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^30.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2解方程(3x+1)(2u-1)=6(x+2)(y-1)(X-2)(y-4)=(x-1)(y-1)
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![(3x^2-2x+1)^2-(3x^2-2x-5)^25/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^30.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2解方程(3x+1)(2u-1)=6(x+2)(y-1)(X-2)(y-4)=(x-1)(y-1)](/uploads/image/z/2534755-67-5.jpg?t=%283x%5E2-2x%2B1%29%5E2-%283x%5E2-2x-5%29%5E25%2F2%28x-2y%29%5E2n%2A%5B-%282y-x%29%5D%5En%2B1%2A%282x-4y%29%5E30.4%5E4%2A%28-5%2F8%29%5E6%26%2310135%3B%28-0.125%29%5E3%26%2310135%3B%2825%2F16%29%5E2%E8%A7%A3%E6%96%B9%E7%A8%8B%283x%2B1%29%282u-1%29%3D6%28x%2B2%29%28y-1%29%28X-2%29%28y-4%29%3D%28x-1%29%28y-1%29)
(3x^2-2x+1)^2-(3x^2-2x-5)^25/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^30.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2解方程(3x+1)(2u-1)=6(x+2)(y-1)(X-2)(y-4)=(x-1)(y-1)
(3x^2-2x+1)^2-(3x^2-2x-5)^2
5/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^3
0.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2
解方程(3x+1)(2u-1)=6(x+2)(y-1)
(X-2)(y-4)=(x-1)(y-1)
(3x^2-2x+1)^2-(3x^2-2x-5)^25/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^30.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2解方程(3x+1)(2u-1)=6(x+2)(y-1)(X-2)(y-4)=(x-1)(y-1)
(3x^2-2x+1)^2-(3x^2-2x-5)^2=[(3x^2-2x+1)-(3x^2-2x-5)][(3x^2-2x+1)+(3x^2-2x-5)]=12(3x^2-2x-2)
5/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^3=(5/2)(x-2y)^2n* (x-2y)^n* [2^3(x-2y)^3]=20(x-2y)^(3n+3)
(3x+1)(2y-1)=6(x+2)(y-1)
6xy-3x+2y-1=6xy-6x+12y-12
所以3x-10y=-11 -----------------------------------1
(X-2)(y-4)=(x-1)(y-1)
xy-4x-2y+8=xy-x-y+1
所以3x+y=7 -----------------------------------------2
1和2联立解得x=59/33,y=18/11