x2减1分之x2减2x 除于(x-1减 x+1分之2x-1)化简

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x2减1分之x2减2x 除于(x-1减 x+1分之2x-1)化简
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x2减1分之x2减2x 除于(x-1减 x+1分之2x-1)化简
x2减1分之x2减2x 除于(x-1减 x+1分之2x-1)化简

x2减1分之x2减2x 除于(x-1减 x+1分之2x-1)化简
原式=[(x²-2x)/(x²-1)]÷[(x-1)-(2x-1)/(x+1)]= [(x²-2x)/(x²-1)]÷[(x²-2x)/(x-1)]= [(x²-2x)/(x²-1)]×[(x-1)/ (x²-2x)]=1/(x+1)