limx→∞(x^4+3x-1)/(3x^4+4x^2+1)对分式(x^4+3x-1)/(3x^4+4x^2+1)分子分母都除以x^4可得limx→∞(x^4+3x-1)/(3x^4+4x^2+1)=limx→∞(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3追问(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3这一步怎么得1/3的把过
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![limx→∞(x^4+3x-1)/(3x^4+4x^2+1)对分式(x^4+3x-1)/(3x^4+4x^2+1)分子分母都除以x^4可得limx→∞(x^4+3x-1)/(3x^4+4x^2+1)=limx→∞(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3追问(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3这一步怎么得1/3的把过](/uploads/image/z/2541733-61-3.jpg?t=limx%E2%86%92%E2%88%9E%28x%5E4%2B3x-1%29%2F%283x%5E4%2B4x%5E2%2B1%29%E5%AF%B9%E5%88%86%E5%BC%8F%28x%5E4%2B3x-1%29%2F%283x%5E4%2B4x%5E2%2B1%29%E5%88%86%E5%AD%90%E5%88%86%E6%AF%8D%E9%83%BD%E9%99%A4%E4%BB%A5x%5E4%E5%8F%AF%E5%BE%97limx%E2%86%92%E2%88%9E%28x%5E4%2B3x-1%29%2F%283x%5E4%2B4x%5E2%2B1%29%3Dlimx%E2%86%92%E2%88%9E%281%2B3%2Fx%5E3-1%2Fx%5E4%29%2F%283%2B4%2Fx%5E2%2B1%2Fx%5E4%29%3D1%2F3%E8%BF%BD%E9%97%AE%281%2B3%2Fx%5E3-1%2Fx%5E4%29%2F%283%2B4%2Fx%5E2%2B1%2Fx%5E4%29%3D1%2F3%E8%BF%99%E4%B8%80%E6%AD%A5%E6%80%8E%E4%B9%88%E5%BE%971%2F3%E7%9A%84%E6%8A%8A%E8%BF%87)
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limx→∞(x^4+3x-1)/(3x^4+4x^2+1)对分式(x^4+3x-1)/(3x^4+4x^2+1)分子分母都除以x^4可得limx→∞(x^4+3x-1)/(3x^4+4x^2+1)=limx→∞(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3追问(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3这一步怎么得1/3的把过
limx→∞(x^4+3x-1)/(3x^4+4x^2+1)
对分式(x^4+3x-1)/(3x^4+4x^2+1)分子分母都除以x^4可得
limx→∞(x^4+3x-1)/(3x^4+4x^2+1)=limx→∞(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3追问(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3这一步怎么得1/3的把过程写出来.
limx→∞(x^4+3x-1)/(3x^4+4x^2+1)对分式(x^4+3x-1)/(3x^4+4x^2+1)分子分母都除以x^4可得limx→∞(x^4+3x-1)/(3x^4+4x^2+1)=limx→∞(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3追问(1+3/x^3-1/x^4)/(3+4/x^2+1/x^4)=1/3这一步怎么得1/3的把过
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