求y=(sinx)^2·cosx的值域 (0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 01:13:30
![求y=(sinx)^2·cosx的值域 (0](/uploads/image/z/2541937-49-7.jpg?t=%E6%B1%82y%3D%28sinx%29%5E2%C2%B7cosx%E7%9A%84%E5%80%BC%E5%9F%9F+%280)
x){V83B3Z6y:MR>A56F#/!zQe\\P6 cu.QkeƵqƶF`
q -&0W "u2ַ/.H̳y Y
求y=(sinx)^2·cosx的值域 (0 求y=(sinx)^2·cosx的值域 (0
求y=(sinx)^2·cosx的值域 (0
求y=(sinx)^2·cosx
2y^2=(sinx)^2*(sinx)^2* [2(cosx)^2]
≤ {[(sinx)^2+(sinx)^2+2(cosx)^2]/3}^3=8/27
y^≤ 4/27
0≤ y≤ 2√3/9