求不定积分∫(2x²)/(x²+1)dx
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![求不定积分∫(2x²)/(x²+1)dx](/uploads/image/z/2541941-53-1.jpg?t=%E6%B1%82%E4%B8%8D%E5%AE%9A%E7%A7%AF%E5%88%86%E2%88%AB%282x%26%23178%3B%29%2F%28x%26%23178%3B%2B1%29dx)
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求不定积分∫(2x²)/(x²+1)dx
求不定积分∫(2x²)/(x²+1)dx
求不定积分∫(2x²)/(x²+1)dx
差不多就这样
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