已知f(x)为一次函数,若f[f(x)]=4x+8求的解析式设原函数f(x)=ax+bf(f(x))=a(ax+b)+b=a^2x+ab+b=4x+8 → 这里不是应该是f(a^2x+ab+b)=4x+8a^2=4吗ab+b=8∴a=2 b=8/3或a=-2 b=-8∴f(x)=2x+8/3f(x)=-2x-8
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![已知f(x)为一次函数,若f[f(x)]=4x+8求的解析式设原函数f(x)=ax+bf(f(x))=a(ax+b)+b=a^2x+ab+b=4x+8 → 这里不是应该是f(a^2x+ab+b)=4x+8a^2=4吗ab+b=8∴a=2 b=8/3或a=-2 b=-8∴f(x)=2x+8/3f(x)=-2x-8](/uploads/image/z/2542834-10-4.jpg?t=%E5%B7%B2%E7%9F%A5f%28x%29%E4%B8%BA%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0%2C%E8%8B%A5f%5Bf%28x%29%5D%3D4x%2B8%E6%B1%82%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E8%AE%BE%E5%8E%9F%E5%87%BD%E6%95%B0f%28x%29%3Dax%2Bbf%28f%28x%29%29%3Da%28ax%2Bb%29%2Bb%3Da%5E2x%2Bab%2Bb%3D4x%2B8+%E2%86%92+%E8%BF%99%E9%87%8C%E4%B8%8D%E6%98%AF%E5%BA%94%E8%AF%A5%E6%98%AFf%EF%BC%88a%5E2x%2Bab%2Bb%EF%BC%89%3D4x%2B8a%5E2%3D4%E5%90%97ab%2Bb%3D8%E2%88%B4a%3D2+b%3D8%2F3%E6%88%96a%3D-2+b%3D-8%E2%88%B4f%28x%29%3D2x%2B8%2F3f%28x%29%3D-2x-8)
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