100/(X+3)+240/(X-1)=(100+240)/X怎么解.回答出来符合我的要求就给分.按照解一元一次分式来解,格式为方程两边同乘以……

1/3x=x-240 x=?求x 1/X(X+1)+1/(X+1)(X+2)+1/(X+2)(X+3).+1/(X+99)(X+100)= 解方程：2x+4x+6x...+100x=1-(x+3x+5x+...+99x) 1X+2X+3X…+98X+99X+100X=50500X X等于多少? 1x+2x+3x+4x+5x+6x+7x…+99x=100 已知x^4+x^3+x^3+x^2+x^1+1=0,求x^100+x^99+x^98+x^97+x^96的值 分母有未知数的一元方程.[100/(x+3)]+[240/(x-1)]=340/x[100/(x+3)]+[240/(x-1)]=340/x求x （X+X)+(X-X)+(X*X)+(X/X)=100 (X+1)X(X+2)X(X+3)=504 f(x)=x(x-1)(x+2)(x-3)(x+4)……(x+100),求f'(1) 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 已知x=100,求x(x+1)分之1+(x+1)(x+2)分之1+(x+2)(x+3)分之1+.+(x+99)(x+100)分之1 1/x(x+1)(x+2)+1/(x+1)(x+2)(x+3).+1/(x+98)(x+99)(x+100)=? x^4+X^3+X^2+X^1+1=0求x^100+X^99+X^98+X^97+X^96的值 已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值. 已知x^4+x^3+x^2+x^2+1=0,求x^100+x^99+x^98+x^97+x^96的值见上 已知x^4+x^3+x^2+x+1=0,求x^100+x^99+x^98+x^97+x^96的值 1/2x-8 x+3x+(1/2x-8)=100 x=?