9(x+y)²-4(x-y)²分解因式=(5x+y)(5y+x),我知道这是答案,但是我希望有详细的过程说明.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 20:39:55
xŒJ0_E%ˊEŮ/2HћRڡ(*NP{^$jInv;Ηz8NcB{fzv~a ϩqG%X
&CyvyND7q"=~;Kk$Oюfɓug&??;LI-,I,`XAL&jƢ0Lu!bSg3V|s>/RmREJԍr(',2+:md#K|/Ɵa>
9(x+y)²-4(x-y)²分解因式=(5x+y)(5y+x),我知道这是答案,但是我希望有详细的过程说明.
9(x+y)²-4(x-y)²分解因式=(5x+y)(5y+x),我知道这是答案,但是我希望有详细的过程说明.
9(x+y)²-4(x-y)²分解因式=(5x+y)(5y+x),我知道这是答案,但是我希望有详细的过程说明.
利用平方差公式
9(x+y)²-4(x-y)²
=[3(x+y)]²-[2(x-y)]²
=[3(x+y)+2(x-y)][3(x+y)-2(x-y)]
=(3x3y+2x-2y)(3x+3y-2x+2y)
=(5x+y)(x+5y)
9(x+y)²-4(x-y)²
=[3(x+y)]^2-[2(x-y)]^2
=[3x+3y]^2-[2x-2y]^2
=(3x+3y+2x-2y)(3x+3y-2x+2y)
=(5x+y)(5y+x)
9(x+y)²-4(x-y)²=[3(x+y)]²-[2(x-y)]²=[3x+3y]²-[2x-2y]²=[(3x+3y)+(2x-2y)]²-[(3x+3y)-(2x-2y)]² =(5x+y)(5y+x).