(1)若|3x-6|+(y+3)²=0,则x-3y=?(2)若|x|=0.5,y²=16,且xy<0,则4xy+2x=?求解!
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(1)若|3x-6|+(y+3)²=0,则x-3y=?(2)若|x|=0.5,y²=16,且xy<0,则4xy+2x=?求解!
(1)若|3x-6|+(y+3)²=0,则x-3y=?(2)若|x|=0.5,y²=16,且xy<0,则4xy+2x=?
求解!
(1)若|3x-6|+(y+3)²=0,则x-3y=?(2)若|x|=0.5,y²=16,且xy<0,则4xy+2x=?求解!
1、
|3x-6|+(y+3)²=0
所以3x-6=0,y+3=0
x=2,y=-3
所以x-3y
=2+9
=11
2、
x=±0.5,y=±4
xy<0则x=-0.5,y=4或x=0.5,y=-4
所以xy=-2
所以原式=4*(-2)+2x
=-8+2x
=-8+1=-7或=-8-1=-9
3x-6=0
x=2
y+3=0
y=-3
x-3y=2+9=11
|x|=0.5
x=±0.5
y^2=16
y=±4
xy<0
xy=-2
4xy+2x
=-8+2x
2x=±1
原式=-9或-7