一元一次方程X²-3X+1=0的两个根分别为x1 x2,则x1²x2+x1x2²的值是
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一元一次方程X²-3X+1=0的两个根分别为x1 x2,则x1²x2+x1x2²的值是
一元一次方程X²-3X+1=0的两个根分别为x1 x2,则x1²x2+x1x2²的值是
一元一次方程X²-3X+1=0的两个根分别为x1 x2,则x1²x2+x1x2²的值是
根据题意得
x1+x2=3
x1x2=1
∴x1²x2+x1x2²
=x1x2(x1+x2)
=1×3
=3
韦达定理
x1+x2=3,x1x2=1
x1²x2+x1x2²=(x1+x2)x1x2=3×1=3
x1+x2=3
x1x2=1
x1²x2+x1x2²
=x1x2(x1+x2)
=1×3
=3