x²+2(1+a)x+3a²+4ab-4b²+2=0有实数根 求a.b的值
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x²+2(1+a)x+3a²+4ab-4b²+2=0有实数根 求a.b的值
x²+2(1+a)x+3a²+4ab-4b²+2=0有实数根 求a.b的值
x²+2(1+a)x+3a²+4ab-4b²+2=0有实数根 求a.b的值
⊿=[2(1+a)]²-4﹙3a²+4ab-4b²+2﹚≧0