若不等式a大于等于-X^2-Y^2-2X-2Y,则实数a的取值范围是

来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 08:26:51
若不等式a大于等于-X^2-Y^2-2X-2Y,则实数a的取值范围是
xQAKA+ 2\ w(0]DHuعeKP :_dgWOfvav7}cV Σ彧`|X!1)sFwukYoaghfc5fSvj#LƄYJ@F9ľC9ԲHw mjU\F #,ɧ:lz?>nφtY&oLnfJ j Xg($PeRH'Ɇn-@#Vhj8oa&,TTCگN;wΒcI2Yr]`2}`}IDd~dA

若不等式a大于等于-X^2-Y^2-2X-2Y,则实数a的取值范围是
若不等式a大于等于-X^2-Y^2-2X-2Y,则实数a的取值范围是

若不等式a大于等于-X^2-Y^2-2X-2Y,则实数a的取值范围是
a≥-x²-y²-2x-2y=2-(x²+2x+1+y²+2y+1)=2-[(x+1)²+(y+1)²]
(x+1)²+(y+1)²≥0 恒成立,则2-[(x+1)²+(y+1)²]≤2
为使 a≥-x²-y²-2x-2y,a的取值范围应该是[2,+∞)

-X^2-Y^2-2X-2Y=-(x^2+2x+1)-(y^2+2y+1)+2
=-(x+1)^2-(y+1)^2+2<=2
a>=-X^2-Y^2-2X-2Y
所以a>=2

x^2+2x+a>=-y^2-2 =>(x+1)^2+y^2>=-(a+2) 由题知此式对一切实数x,y都成立又(x+1)^2+y^2>=0 所以-(a+2)<=0 a>=-2 ..