已知x²-xy=8,xy-y²=3,则x²-y²的值为,x²-2xy+y²的值为
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已知x²-xy=8,xy-y²=3,则x²-y²的值为,x²-2xy+y²的值为
已知x²-xy=8,xy-y²=3,则x²-y²的值为,x²-2xy+y²的值为
已知x²-xy=8,xy-y²=3,则x²-y²的值为,x²-2xy+y²的值为
两式相加得到x²-y²=11
两式相减得到x²-2xy+y²=5