如图,AC,BD交于点O.已知∠A=∠D=90°,AC=BD,是说明OB=OCD:\My Documents\My Pictures\未命名.bmp
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![如图,AC,BD交于点O.已知∠A=∠D=90°,AC=BD,是说明OB=OCD:\My Documents\My Pictures\未命名.bmp](/uploads/image/z/2561104-64-4.jpg?t=%E5%A6%82%E5%9B%BE%2CAC%2CBD%E4%BA%A4%E4%BA%8E%E7%82%B9O.%E5%B7%B2%E7%9F%A5%E2%88%A0A%3D%E2%88%A0D%3D90%C2%B0%2CAC%3DBD%2C%E6%98%AF%E8%AF%B4%E6%98%8EOB%3DOCD%3A%5CMy+Documents%5CMy+Pictures%5C%E6%9C%AA%E5%91%BD%E5%90%8D.bmp)
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如图,AC,BD交于点O.已知∠A=∠D=90°,AC=BD,是说明OB=OCD:\My Documents\My Pictures\未命名.bmp
如图,AC,BD交于点O.已知∠A=∠D=90°,AC=BD,是说明OB=OC
D:\My Documents\My Pictures\未命名.bmp
如图,AC,BD交于点O.已知∠A=∠D=90°,AC=BD,是说明OB=OCD:\My Documents\My Pictures\未命名.bmp
证明:
连接BC
∵∠A=∠D=90°,AC=BD,BC=BC
∴△ABC≌△DCB
∴∠ACB=∠DBC
∴OB=OC