若(x+y)\2x=(z+x)\2y=(x+y)\2z=k,则k的值是
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若(x+y)\2x=(z+x)\2y=(x+y)\2z=k,则k的值是
若(x+y)\2x=(z+x)\2y=(x+y)\2z=k,则k的值是
若(x+y)\2x=(z+x)\2y=(x+y)\2z=k,则k的值是
已知,(y+z)/2x = (z+x)/2y = (x+y)/2z = k ,
可得:y+z = 2kx ,z+x = 2ky ,x+y = 2kz ,
三式相加可得:2(x+y+z) = 2k(x+y+z) ,
整理得:2(k-1)(x+y+z) = 0 ,
该等式对任意 x、y、z 都成立,
则有:k-1 = 0 ,
解得:k = 1 .
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