如图,在平面直角坐标系中,点B的坐标是(-1,0),点C的坐标是(1,0),点D为y轴上一点,点A是第二象限内一动点,且∠BAC=2∠BDO,过D作DM⊥AC于M(1)求证:∠ABD=∠ACD(2)若点E在BA延长线上,求证:AD平分∠
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![如图,在平面直角坐标系中,点B的坐标是(-1,0),点C的坐标是(1,0),点D为y轴上一点,点A是第二象限内一动点,且∠BAC=2∠BDO,过D作DM⊥AC于M(1)求证:∠ABD=∠ACD(2)若点E在BA延长线上,求证:AD平分∠](/uploads/image/z/2568852-36-2.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E7%82%B9B%E7%9A%84%E5%9D%90%E6%A0%87%E6%98%AF%28-1%2C0%29%2C%E7%82%B9C%E7%9A%84%E5%9D%90%E6%A0%87%E6%98%AF%281%2C0%29%2C%E7%82%B9D%E4%B8%BAy%E8%BD%B4%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E7%82%B9A%E6%98%AF%E7%AC%AC%E4%BA%8C%E8%B1%A1%E9%99%90%E5%86%85%E4%B8%80%E5%8A%A8%E7%82%B9%2C%E4%B8%94%E2%88%A0BAC%3D2%E2%88%A0BDO%2C%E8%BF%87D%E4%BD%9CDM%E2%8A%A5AC%E4%BA%8EM%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9A%E2%88%A0ABD%3D%E2%88%A0ACD%EF%BC%882%EF%BC%89%E8%8B%A5%E7%82%B9E%E5%9C%A8BA%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%2C%E6%B1%82%E8%AF%81%EF%BC%9AAD%E5%B9%B3%E5%88%86%E2%88%A0)
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