计算:(1+2)(1+2²)(1+2的四次方)(1+2的八次方),
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![计算:(1+2)(1+2²)(1+2的四次方)(1+2的八次方),](/uploads/image/z/2579370-42-0.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%EF%BC%881%2B2%EF%BC%89%EF%BC%881%EF%BC%8B2%26%23178%3B%EF%BC%89%EF%BC%881%2B2%E7%9A%84%E5%9B%9B%E6%AC%A1%E6%96%B9%EF%BC%89%EF%BC%881%EF%BC%8B2%E7%9A%84%E5%85%AB%E6%AC%A1%E6%96%B9%EF%BC%89%2C)
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计算:(1+2)(1+2²)(1+2的四次方)(1+2的八次方),
计算:(1+2)(1+2²)(1+2的四次方)(1+2的八次方),
计算:(1+2)(1+2²)(1+2的四次方)(1+2的八次方),
乘一个(2-1)
(1+2)(1+2²)(1+2的四次方)(1+2的八次方)
=(2-1)(2+1)(2²+1)(2^4+1)(2^8+1)
=(2²-1)(2²+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1
乘以(1-2)得1-2^16
所以原式=2^16-1什么啊,要过程!(1-2)*(1+2)(1+2²)(1+2^4)(1+2^8) 运用平方差公式 =(1-2^2)*(1+2²)(1+2^4)(1+2^8) =(1-2^4)*(1+2^4)(1+2^8) =1-2^16你和你第一个算的数哪个对啊、乘以1-2=-1,所以所得再除以-1 答案是2^16-1谢谢啊!...
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乘以(1-2)得1-2^16
所以原式=2^16-1
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