计算(2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 06:48:24
计算(2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)
x){nu050jʆ`Y-Og~fi;6IE_`gChTVjjThWjVVAF q8 B"a@HX@$, f@<;'l |`,#VU ] Ʌ1D k|E`)6=tO=s O7>

计算(2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)
计算(2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)

计算(2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)
(x-y)(x+y)=x^2-y^2
(2-1)(2+1)=2^2-1
(2^2-1)(2^2+1)=2^4-1
(2^4-1)(2^4+1)=2^8-1
(2^8-1)(2^8+1)=2^16-1

2-1)(2+1)(2²+1)(2的四次方+1)(2的八次方+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1

(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1
=65535

原式=1×3×5×17×257
=65535
蓝木连