先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/29 15:14:58
先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2
x){gu :OzmlzڰGA(1ISCDjk@BHSٜOvM5I5I*ҧD~ R 5IJJJҶ1̀D!IL06NEXi pZFZtjftBL024/.H̳yV(~

先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2
先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2

先化简,再求值 (2ab)(-2ab)+(3ab)(3ab+2),期中a-3,b=2
(2ab)(-2ab)+(3ab)(3ab+2)
=-4a*a*b*b+9a*a*b*b+6a*b
=5a*a*b*b+6ab
=ab(5ab+6)
a=3,b=2
那么 ab(5ab+6)=3*2*(5*3*2+6)
=216