已知x-y=3,求代数式(x+y)(x-y)+(x-y)²-(2xy-2y)²的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/02 16:04:56
已知x-y=3,求代数式(x+y)(x-y)+(x-y)²-(2xy-2y)²的值
x){}K+t+mumlz{BRS( &Ք -uFF0Z6I*ҧYv6u3+|s] =F q[# EӍF 1>0h׀aSIeHRE=^4}ڱOv=58܆p/&

已知x-y=3,求代数式(x+y)(x-y)+(x-y)²-(2xy-2y)²的值
已知x-y=3,求代数式(x+y)(x-y)+(x-y)²-(2xy-2y)²的值

已知x-y=3,求代数式(x+y)(x-y)+(x-y)²-(2xy-2y)²的值
﹙x-y﹚﹙x+y+x-y-2y﹚=2﹙x-y﹚﹙x-y﹚=2×3×3=18

(x+y)(x-y)+(x-y)²-(2xy-2y)²
=(x+y)(x-y)+(x-y)²-4y^2(x-1)²
=-4y^2(x-1)²
只能到这了啊

(x+y)(x-y)+(x-y)²-(2xy-2y)²
=(x+y)(x-y)+(x-y)²-4y^2(x-1)²
=-4y^2(x-1)²