设m-n=1/4,m+n=2,求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]●1/(m-n)的值
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设m-n=1/4,m+n=2,求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]●1/(m-n)的值
设m-n=1/4,m+n=2,求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]●1/(m-n)的值
设m-n=1/4,m+n=2,求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]●1/(m-n)的值
设m-n=1/4,m+n=2,2m=9/4 m=9/8,n=2-9/8=-1/8
求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]1/(m-n)=[(mn)²/(m+n)²-2/mn÷(m+n)/mn]*1/(m-n)
=[mn)²/2²-2/mn*mn/2]*(-4)=[9/64*1/3]*(-4)=-3/16
用完全平方公式啊,先化简所要求的式子,再转化已知条件。