作业帮[（1/m)-(1/n)]/[(m²-2mn+n²)/mn]
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/18 12:17:05
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[（1/m)-(1/n)]/[(m²-2mn+n²)/mn]
[（1/m)-(1/n)]/[(m²-2mn+n²)/mn]
[（1/m)-(1/n)]/[(m²-2mn+n²)/mn]
原式=(n-m)/(mn)÷[(m-n)²/(mn)]
=(n-m)/(mn)×(mn)/(m-n)²;
=1/(n-m);
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