(1)把二次函数y=-3/4x2+2/3x+9/4变成y=a(x-h)2+k的形式(2)写出抛物线(2)写出抛物线y=-3/4x2+2/3x+9/4的顶点坐标和对称轴,并说明该抛物线是由哪一条形如y=ax2的抛物线经过怎样的变换得到的?
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![(1)把二次函数y=-3/4x2+2/3x+9/4变成y=a(x-h)2+k的形式(2)写出抛物线(2)写出抛物线y=-3/4x2+2/3x+9/4的顶点坐标和对称轴,并说明该抛物线是由哪一条形如y=ax2的抛物线经过怎样的变换得到的?](/uploads/image/z/2587786-34-6.jpg?t=%281%29%E6%8A%8A%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0y%3D-3%2F4x2%2B2%2F3x%2B9%2F4%E5%8F%98%E6%88%90y%3Da%28x-h%292%2Bk%E7%9A%84%E5%BD%A2%E5%BC%8F%282%29%E5%86%99%E5%87%BA%E6%8A%9B%E7%89%A9%E7%BA%BF%282%29%E5%86%99%E5%87%BA%E6%8A%9B%E7%89%A9%E7%BA%BFy%3D-3%2F4x2%2B2%2F3x%2B9%2F4%E7%9A%84%E9%A1%B6%E7%82%B9%E5%9D%90%E6%A0%87%E5%92%8C%E5%AF%B9%E7%A7%B0%E8%BD%B4%2C%E5%B9%B6%E8%AF%B4%E6%98%8E%E8%AF%A5%E6%8A%9B%E7%89%A9%E7%BA%BF%E6%98%AF%E7%94%B1%E5%93%AA%E4%B8%80%E6%9D%A1%E5%BD%A2%E5%A6%82y%3Dax2%E7%9A%84%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%BB%8F%E8%BF%87%E6%80%8E%E6%A0%B7%E7%9A%84%E5%8F%98%E6%8D%A2%E5%BE%97%E5%88%B0%E7%9A%84%3F)
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(1)把二次函数y=-3/4x2+2/3x+9/4变成y=a(x-h)2+k的形式(2)写出抛物线(2)写出抛物线y=-3/4x2+2/3x+9/4的顶点坐标和对称轴,并说明该抛物线是由哪一条形如y=ax2的抛物线经过怎样的变换得到的?
(1)把二次函数y=-3/4x2+2/3x+9/4变成y=a(x-h)2+k的形式(2)写出抛物线
(2)写出抛物线y=-3/4x2+2/3x+9/4的顶点坐标和对称轴,并说明该抛物线是由哪一条形如y=ax2的抛物线经过怎样的变换得到的?
(1)把二次函数y=-3/4x2+2/3x+9/4变成y=a(x-h)2+k的形式(2)写出抛物线(2)写出抛物线y=-3/4x2+2/3x+9/4的顶点坐标和对称轴,并说明该抛物线是由哪一条形如y=ax2的抛物线经过怎样的变换得到的?
(1)y=-3/4 x²+2/3 x+9/4
=-3/4(x-4/9)²+259/108
(2)该抛物线的顶点坐标是(4/9, 259/108);
该抛物线的对称轴是:直线 x=4/9;
该抛物线是由抛物线y=-3/4 x²沿x轴向右平移4/9个单位后,再沿y轴向上平移259/108个单位得到的.
(1) y=-3/4(x-4/9)^2+259/108 a=-3/4 h=4/9 k=259/108
(2) 由y=-3/4x^2 向右移动4/9 ,向上移动259/108 得到