若(x-3)²+|x+y-5|=0,求x²+y²
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若(x-3)²+|x+y-5|=0,求x²+y²
若(x-3)²+|x+y-5|=0,求x²+y²
若(x-3)²+|x+y-5|=0,求x²+y²
(x-3)^2+|x+y-5|=0
(x-3)^2=0 x=3
|x+y-5|=0 y=2
x^2+y^2=9+4=13
由题可以得出
x-3=0而且x+y-5=0
解出 x=3,y=2
因此 x^2+y^2=3^2+2^2=13