若|x-1|+(y+2)²=0,则(x+y)²ⁿ+¹
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若|x-1|+(y+2)²=0,则(x+y)²ⁿ+¹
若|x-1|+(y+2)²=0,则(x+y)²ⁿ+¹
若|x-1|+(y+2)²=0,则(x+y)²ⁿ+¹
|x-1|+(y+2)²=0
所以x-1=0,y+2=0
所以x=1,y=-2
x+y=-1
因为2n+1是奇数
所以原式=-1
|x-1|+(y+2)²=0,则x-1=y+2=0,x=1,y=-2
(x+y)²ⁿ+¹=(1-2)²ⁿ+¹=-1