(a+2b)²+______=a²+2ab+4b²若x²+2x=1,则(x+1)²=

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(a+2b)²+______=a²+2ab+4b²若x²+2x=1,则(x+1)²=
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(a+2b)²+______=a²+2ab+4b²若x²+2x=1,则(x+1)²=
(a+2b)²+______=a²+2ab+4b²
若x²+2x=1,则(x+1)²=

(a+2b)²+______=a²+2ab+4b²若x²+2x=1,则(x+1)²=
(a+2b)²+_(-2ab)_____=a²+2ab+4b²
(x+1)^2
=x^2+2x+1
∵x^2+2x=1
∴(x+1)^2=1+1=2
若x²+2x=1,则(x+1)²=(2)

(a+2b)²=a²+4b²+4ab
所以(a+2b)²+(-2ab)=a²+2ab+4b²
(x+1)²=x²+2x+1=1+1=2