计算:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2" (2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/31 02:41:44
![计算:(1)](/uploads/image/z/2604835-19-5.jpg?t=%E8%AE%A1%E7%AE%97%EF%BC%9A%281%29%221%2F6x-4y%22%2B%221%2F6x%2B4y%22-%223x%2F4y%5E2-9x%5E2%22+%282%291-%28a-+%221%2F1-a%22%29%5E2%E9%99%A4%E4%BB%A5%22a%5E2-a%2B1%2Fa%5E2-2a%2B1%22)
计算:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2" (2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
计算:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2" (2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
计算:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2" (2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2"
=1/(2(3x-2y))+1/(2(3x+2y))-3x/((2y-3x)(2y+3x))
=((3x+2y)+(3x-2y)+2*3x))/(2(3x-2y)(2y+3x))
=6x/((3x-2y)(2y+3x))
=6x/(9x^2-4y^2)
(2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
=[(1-a)^2+(1-a)]/(1-a)^2 除以"a^2-a+1/(a-1)^2"
=(2-3a+a^2)/(a^2-a+1)
(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2"
=(6x+4y+6x-4y)/[(6x+4y)(6x-4y)]-3x/[(2y-3x)(2y+3x)]
=12x/[(6x+4y)(6x-4y)]+3x/[(3x-2y)(3x+2yx)]
=3x/[(3x+2y)(3x-2y)]+3x/[(3x-2y)(3x+2yx)]
=6x/(9x^2...
全部展开
(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2"
=(6x+4y+6x-4y)/[(6x+4y)(6x-4y)]-3x/[(2y-3x)(2y+3x)]
=12x/[(6x+4y)(6x-4y)]+3x/[(3x-2y)(3x+2yx)]
=3x/[(3x+2y)(3x-2y)]+3x/[(3x-2y)(3x+2yx)]
=6x/(9x^2-4y^2)
(2)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1"
=1-[(a-a^2-1)/(1-a)]/[(a^2-a+1)/(a-1)^2]
=1+[(a^2-a+1)/(1-a)]/[(a^2-a+1)/(1-a)^2]
=1+[(a^2-a+1)(1-a)^2]/[(1-a)(a^2-a+1)]
=1+1-a
=2-a
收起
:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2"
=[(6x+4y)+(6x-4y)]/(6x+4y)(6x-4y)-3x/(2y+3x)(2y-3x)
=12x/4(3x-2y)(3x+2y)-3x/(2y+3x)(2y-3x)
=(12x+3x*4)/4(3x-2y)(3x+2y)
=6x/(9x^2-4y^2)
)1-(a-...
全部展开
:(1)"1/6x-4y"+"1/6x+4y"-"3x/4y^2-9x^2"
=[(6x+4y)+(6x-4y)]/(6x+4y)(6x-4y)-3x/(2y+3x)(2y-3x)
=12x/4(3x-2y)(3x+2y)-3x/(2y+3x)(2y-3x)
=(12x+3x*4)/4(3x-2y)(3x+2y)
=6x/(9x^2-4y^2)
)1-(a- "1/1-a")^2除以"a^2-a+1/a^2-2a+1
=1-(a-a^2-1/1-a)^2/[a^2-a+1/(1-a)^2]
=(2a^2-3a+2)/(1-a)^2*[(1-a)^2/(a^2-a+1)]
=(2a^2-3a+2)/(a^2-a+1)
收起