计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分(根号2/(1+i))^100+ (根号2/(1-i))^100
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/29 16:11:16
x){nu~Odz;o72
38Cm
n&HiGzl)lW*"p15eCs8SP"m `jL!&DV!d
Lt;@piG =mX!:
m
0%.!0'$فR q(
计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分(根号2/(1+i))^100+ (根号2/(1-i))^100
计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分
(根号2/(1+i))^100+ (根号2/(1-i))^100
计算:(根号2/(1+i))^100+ (根号2/(1-i))^1000分(根号2/(1+i))^100+ (根号2/(1-i))^100
(1+i)^100
=[(1+i)²]^50
=(1+i²+2i)^50
=[(2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(1-i)^100
=[(1-i)²]^50
=(1+i²-2i)^50
=[(-2i)²]^25
=-4^25
=-(2²)^25
=-2^50
(根号2/(1+i))^100+ (根号2/(1-i))^100
=2^50/(1+i)^100+ 2^50/(1-i)^100
=2^50/(-2^50) + 2^50/(-2^50)
=-1-1
=-2