设集合M={x|y²=3x,x∈R},N={y|x²+y²=4,x∈R,y∈R},则M∩N等于
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设集合M={x|y²=3x,x∈R},N={y|x²+y²=4,x∈R,y∈R},则M∩N等于
设集合M={x|y²=3x,x∈R},N={y|x²+y²=4,x∈R,y∈R},则M∩N等于
设集合M={x|y²=3x,x∈R},N={y|x²+y²=4,x∈R,y∈R},则M∩N等于
M∩N=[-2,2]
为什么呢?
M={x|y²=3x,x∈R},所以M就是全部x的取值范围,和y²=3x无关,M=R
N={y|x²+y²=4,x∈R,y∈R},同理N是全部y的取值范围,显然y∈[-2,2]
所以M∩N=[-2,2]
y²=3x
x²+y²=4 ===> x²+3x=4
===> x²+3x-4=0
===> (x+4)(x-1)=0
===> x=-4,x=1
而,y²=3x≥0
所以,x=1
则,M∩N={1}
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