化简:(sinx+sin2x)/(1+cosx+cos2x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 10:00:20
![化简:(sinx+sin2x)/(1+cosx+cos2x)](/uploads/image/z/2624154-42-4.jpg?t=%E5%8C%96%E7%AE%80%3A%28sinx%2Bsin2x%29%2F%281%2Bcosx%2Bcos2x%29)
x){3+̼
m aTa_\"\"}bmB4 E`.PQ,gju6<ٽi{aϓ@fu$U$AlhBdF.3@ )*[pZ;HlݠqҌ3*Cq>f T
化简:(sinx+sin2x)/(1+cosx+cos2x)
化简:(sinx+sin2x)/(1+cosx+cos2x)
化简:(sinx+sin2x)/(1+cosx+cos2x)
sinx+sin2x=sinx+2sinxcosx=sinx(1+2cosx)
1+cosx+cos2x=2cosx^2+cosx=cosx(1+2cosx)
所以原式比值为:sinx/cosx=tanx
(sinx+2sinxcosx)(1+cosx+2cos(2)x-1)=sinx(1+2cosx)(1+2cosx)sinx=sin(2)x(1+2cosx)
(sinx+sin2x)/(1+cosx+cos2x)
=(sinx+2sinxcosx)/(cosx+2(cosx)^2)
=sinx(1+2cosx)/cosx(1+2cosx)
=tanx