已知函数f(x)=x²+x-1,α,β是方程f(x)=0的两个根(α>β)f'(x)是f(x)的导数,设a1=1,an+1=an-f(aan+1=an-f(an)÷f"(an)(n=1.2.3...)(1)求α,β的值(2)证明任意的正整数n都有an>α(3)记bn=ln(an-β)/(an-
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 14:29:40
![已知函数f(x)=x²+x-1,α,β是方程f(x)=0的两个根(α>β)f'(x)是f(x)的导数,设a1=1,an+1=an-f(aan+1=an-f(an)÷f](/uploads/image/z/2624242-58-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%3Dx%26sup2%3B%2Bx-1%2C%CE%B1%2C%CE%B2%E6%98%AF%E6%96%B9%E7%A8%8Bf%28x%EF%BC%89%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%A0%B9%EF%BC%88%CE%B1%EF%BC%9E%CE%B2%EF%BC%89f%27%28x%29%E6%98%AFf%28x%EF%BC%89%E7%9A%84%E5%AF%BC%E6%95%B0%2C%E8%AE%BEa1%3D1%2Can%2B1%3Dan-f%28aan%2B1%3Dan-f%28an%29%C3%B7f%22%28an%29%28n%3D1.2.3...%29%281%29%E6%B1%82%CE%B1%2C%CE%B2%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E8%AF%81%E6%98%8E%E4%BB%BB%E6%84%8F%E7%9A%84%E6%AD%A3%E6%95%B4%E6%95%B0n%E9%83%BD%E6%9C%89an%EF%BC%9E%CE%B1%EF%BC%883%EF%BC%89%E8%AE%B0bn%3Dln%28an%EF%BC%8D%CE%B2%EF%BC%89%EF%BC%8F%EF%BC%88an-)
xZ]$U+WoA XyуUΟ|'ҽ_
`0nnCk'8in_k7b?}@\q[|^r] EtQtq gy8_?m_P\z;O
}Dwa{o=}a5q66ܙöfWGv#kҦf/lC^k˷FvGOFG;ѽ㟅 S
Vۯ,o݀o[g!w^'7zus;>ç뮨!/_w>o
._ί4,Ju\߸te=eSډQBUisΧFdE;6~!qS(J_c0jsUU(gD<ާge*
2g#uhs3եD4q
m=I*9T[TRk-ֽV]nDN3#ZqsyRg*;3K7u+{h6v1R0
F3a4X>CLZTvV-(5kYt`DBNOlMS<\anJ 71<(2㰍3[x!8qzeBC;WC,p+̹~}`DH2dOU$;x:Ib'5=fmb=M!6UfPCqQʺ EJ;MbLgۨ.%R㱞/H̔IFm( r.U]hPّ/M}4٘H6<1ujh>7{#93#7Q@@Ls snjZ, O@}S۸%ר4DVdY3 Rd ߢ|!+(wPCZ]HC#}<)߽3g3q%$v`VT"%uDJvw