化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5α ..1/4 sin4α 、
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![化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5α ..1/4 sin4α 、](/uploads/image/z/2624672-56-2.jpg?t=%E5%8C%96%E7%AE%80%E6%A0%B9%E5%8F%B7%E4%B8%8B1%2Bcos%283%CF%80-%CE%B8%29%2F2+%283%CF%80%2F2%EF%BC%9C%CE%B8%EF%BC%9C2%CF%80%29+sin+%CE%B8%2F2+%E6%80%8E%E7%AE%97%3F%E5%8C%96%E7%AE%80%EF%BC%9Asin%CE%B1%2Acos%5E5%CE%B1+-cos%CE%B1sin%5E5%E5%8C%96%E7%AE%80%E6%A0%B9%E5%8F%B7%E4%B8%8B1%2Bcos%283%CF%80-%CE%B8%29%2F2+%283%CF%80%2F2%EF%BC%9C%CE%B8%EF%BC%9C2%CF%80%29+sin+%CE%B8%2F2+%E6%80%8E%E7%AE%97%3F%E5%8C%96%E7%AE%80%EF%BC%9Asin%CE%B1%2Acos%5E5%CE%B1+-cos%CE%B1sin%5E5%CE%B1+..1%2F4+sin4%CE%B1+%E3%80%81)
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化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5α ..1/4 sin4α 、
化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5
化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?
化简:sinα*cos^5α -cosαsin^5α ..1/4 sin4α 、
化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5化简根号下1+cos(3π-θ)/2 (3π/2<θ<2π) sin θ/2 怎算?化简:sinα*cos^5α -cosαsin^5α ..1/4 sin4α 、
根号下1+cos(3π-θ)/2 =根号下1+cos(π+θ)/2=根号下(1-cosθ)/2
=根号下2sin²θ/2=根号下sin²θ/2
因为3π/2<θ<2π,所以3π/4<θ/2<π 即θ/2是第二象限的,sinθ/2>0
所以原式=sinθ/2
sinα*cos^5α -cosαsin^5α=sinαcosα(cos^4α-sin^4α)
=sinαcosα(cos²α+sin²α)(cos²α-sin²α)
=sinαcosα cos2α=1/2 sin2αcos2α
=1/4sin4α