作业帮1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10麻烦你帮帮忙了,期末考了,我真是一塌糊涂啊~利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3题目又弄
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![1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10麻烦你帮帮忙了,期末考了,我真是一塌糊涂啊~利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3题目又弄](/uploads/image/z/2624724-36-4.jpg?t=1.%E5%88%A9%E7%94%A8%E5%AF%B9%E6%95%B0%E6%B1%82%E5%AF%BC%E6%B3%95%E6%B1%82%E5%AF%BC%3Ay%3D%5B%28x-1%29x%28x%2B1%29%28x%2B2%29%2F%28x-2%29%5E2%28x%2B3%29%5D1%2F3+2.%E6%B1%82%E4%BA%8C%E9%98%B6%E5%AF%BC%E6%95%B0%EF%BC%88y%60%60%EF%BC%89%EF%BC%9Ay%3D%28x%5E2-2x%2B5%29%5E10%E9%BA%BB%E7%83%A6%E4%BD%A0%E5%B8%AE%E5%B8%AE%E5%BF%99%E4%BA%86%2C%E6%9C%9F%E6%9C%AB%E8%80%83%E4%BA%86%2C%E6%88%91%E7%9C%9F%E6%98%AF%E4%B8%80%E5%A1%8C%E7%B3%8A%E6%B6%82%E5%95%8A%7E%E5%88%A9%E7%94%A8%E5%AF%B9%E6%95%B0%E6%B1%82%E5%AF%BC%E6%B3%95%E6%B1%82%E5%AF%BC%3Ay%3D%5B%28x-1%29x%28x%2B1%29%28x%2B2%29%2F%28x-2%29%5E2%28x%2B3%29%5D%5E1%2F3%E9%A2%98%E7%9B%AE%E5%8F%88%E5%BC%84)
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1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10麻烦你帮帮忙了,期末考了,我真是一塌糊涂啊~利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3题目又弄
1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10
麻烦你帮帮忙了,期末考了,我真是一塌糊涂啊~
利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3题目又弄错了难怪没人理我呢~呵呵
1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10麻烦你帮帮忙了,期末考了,我真是一塌糊涂啊~利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3题目又弄
1.两边分别求导,左边＝(lny)'=y'lny,右边对数乘除可以化为加减,这样方便求导,左右相等就可以得到结果.你那式子写的存在歧义,把正确的式子自己算下就好了.
2.同上求得y',再计算y"