f(cosx)=cos2x,则f(sinx)的表达式f(cos(π/2-x) )怎么就等于-cos2x呢?
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f(cosx)=cos2x,则f(sinx)的表达式f(cos(π/2-x) )怎么就等于-cos2x呢?
f(cosx)=cos2x,则f(sinx)的表达式
f(cos(π/2-x) )怎么就等于-cos2x呢?
f(cosx)=cos2x,则f(sinx)的表达式f(cos(π/2-x) )怎么就等于-cos2x呢?
f(cosx)=cos2x
sinx=cos(π/2-x)
f(sinx)=f[cos(π/2-x)]=cos(π-2x)=-cos2x
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