已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z

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已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z
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已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z
已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z

已知X/2=Y/3=Z/4≠0,求2x+3y-z/x+2y-3z
令a=X/2=Y/3=Z/4
X=2a
Y=3a
Z=4a
所以原式=(4a+9a-4a)/(2a+6a-12a)
=9a/(-4a)
=-9/4

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