若a²b²+a²+b²-4ab+1=0,则a=____,b=_____.
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若a²b²+a²+b²-4ab+1=0,则a=____,b=_____.
若a²b²+a²+b²-4ab+1=0,则a=____,b=_____.
若a²b²+a²+b²-4ab+1=0,则a=____,b=_____.
将已知等式变形得:a²b²+1-2ab+a²+b²-2ab=0
(ab-1)²+(a-b)²=0
∴易知ab-1=0,a-b=0
∴a1=1,b1=1;a2=-1,b2=-1