如图,EB和DC相交于点A,CF、EF分别平分∠ACB、∠AED.若∠B=70°,∠D=40°,则∠F的度数为···········( )(A)55° (B)56° (C)57° (D)58°
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![如图,EB和DC相交于点A,CF、EF分别平分∠ACB、∠AED.若∠B=70°,∠D=40°,则∠F的度数为···········( )(A)55° (B)56° (C)57° (D)58°](/uploads/image/z/2640777-33-7.jpg?t=%E5%A6%82%E5%9B%BE%2CEB%E5%92%8CDC%E7%9B%B8%E4%BA%A4%E4%BA%8E%E7%82%B9A%2CCF%E3%80%81EF%E5%88%86%E5%88%AB%E5%B9%B3%E5%88%86%E2%88%A0ACB%E3%80%81%E2%88%A0AED.%E8%8B%A5%E2%88%A0B%3D70%C2%B0%2C%E2%88%A0D%3D40%C2%B0%2C%E5%88%99%E2%88%A0F%E7%9A%84%E5%BA%A6%E6%95%B0%E4%B8%BA%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%C2%B7%EF%BC%88+%EF%BC%89%EF%BC%88A%EF%BC%8955%C2%B0+%EF%BC%88B%2956%C2%B0+%EF%BC%88C%EF%BC%8957%C2%B0+%EF%BC%88D%EF%BC%8958%C2%B0)
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如图,EB和DC相交于点A,CF、EF分别平分∠ACB、∠AED.若∠B=70°,∠D=40°,则∠F的度数为···········( )(A)55° (B)56° (C)57° (D)58°
如图,EB和DC相交于点A,CF、EF分别平分∠ACB、∠AED.若∠B=70°,∠D=40°,则∠F的度数为···········( )
(A)55° (B)56° (C)57° (D)58°
如图,EB和DC相交于点A,CF、EF分别平分∠ACB、∠AED.若∠B=70°,∠D=40°,则∠F的度数为···········( )(A)55° (B)56° (C)57° (D)58°
A
∠F+1/2∠ACB=∠D+1/2∠AED
∠F=∠D+1/2(∠AED-∠ACB)
又∠AED+∠D=∠B+∠ACB
所以∠F=40+1/2(70-40)=55
简单啊