若a²-2ab+8b²等于0 (ab不等于0)则a/b=
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若a²-2ab+8b²等于0 (ab不等于0)则a/b=
若a²-2ab+8b²等于0 (ab不等于0)则a/b=
若a²-2ab+8b²等于0 (ab不等于0)则a/b=
有个新解法,
因为ab=/0
则b=/0
等式两边除以b^2变成
(a/b)^2-2(a/b)+8=0
吧a/b当做一个整体给配平方[(a/b)-1]^2+7=0
所以a/b=1+-√7i
楼主啊,觉得我的解得妙就推荐下么,我想升级滴,
a²-2ab+8b²=0
a²/b²-2a/b+8=0
(a/b)²-2(a/b)+8=0
判别式=4-4*8=-28<0
所以实数范围内无解
则a/b不存在
a²-2ab+8b²=0
a²-2ab+b²+7b²=0
(a-b)²+7b²=0
(a-b+√7ib)(a-b-√7ib)=0
a1=(1-√7i)b, a/b=(1-√7i)
a2=(1+√7i)b, a/b=(1+√7i)