(a²+b²-1)-4a²b²因式分解
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(a²+b²-1)-4a²b²因式分解
(a²+b²-1)-4a²b²因式分解
(a²+b²-1)-4a²b²因式分解
题无解,如为(a²+b²-1)²-4a²b²则有解
看两个为独立整体.
满足x^2-y^2=(x+y)(x-y)
把相应的代进去,[(a²+b²-1)+(2ab)][(a²+b²-1)-(2ab)]
=(a²+2ab+b²-1)(a²-2ab+b²-1)
=[(a+b)^2-1][(a-b)^2-1]
又可看到=(a+b+1)(a+b-1)(a-b+1)(a-b-1)