x2-2xy=0,x2-y2+2y-1+0

x2-2xy=0,x2-y2+2y-1+0
x2-2xy=0,x2-y2+2y-1+0

x2-2xy=0,x2-y2+2y-1+0
x²-2xy=x(x-2y)=0 (1)
x²-y²+2y-1=x²-(y-1)²=(x+y-1)(x-y+1)=0 (2)
由(1)得 x=0 (3)
或 x-2y=0 (4)
把(3)代入(2)得 (y-1)²=0
即 y1=y2=1
把(4)代入(2)得 (3y-1)(y+1)=0
从而 y3=1/3 y4=-1
从而得 x4=2/3 x4=-2
原方程的解为
x1=x2=0 y1=y2=1
x3=2/3,y3=1/3
x4=-1 y4=-2

2X(1-Y)=0 X2-(Y-1)2=0
解得x=0 y=1