这个2元关系究竟是如何计算的?R1={(a,b),(c,d)},R2={(b,c),(d,e)}那么R1*R2={(a,c)},R2*R1={(b,d)}我怎么觉得,R1*R2={(a,c),(c,e)}呢,因为(a,b)(b,c)可以得到(a,c)(c,d)(d,e)可以得到(c,e)啊.
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![这个2元关系究竟是如何计算的?R1={(a,b),(c,d)},R2={(b,c),(d,e)}那么R1*R2={(a,c)},R2*R1={(b,d)}我怎么觉得,R1*R2={(a,c),(c,e)}呢,因为(a,b)(b,c)可以得到(a,c)(c,d)(d,e)可以得到(c,e)啊.](/uploads/image/z/2657307-3-7.jpg?t=%E8%BF%99%E4%B8%AA2%E5%85%83%E5%85%B3%E7%B3%BB%E7%A9%B6%E7%AB%9F%E6%98%AF%E5%A6%82%E4%BD%95%E8%AE%A1%E7%AE%97%E7%9A%84%3FR1%3D%7B%28a%2Cb%29%2C%28c%2Cd%29%7D%2CR2%3D%7B%28b%2Cc%29%2C%28d%2Ce%29%7D%E9%82%A3%E4%B9%88R1%2AR2%3D%7B%28a%2Cc%29%7D%2CR2%2AR1%3D%7B%28b%2Cd%29%7D%E6%88%91%E6%80%8E%E4%B9%88%E8%A7%89%E5%BE%97%2CR1%2AR2%3D%7B%28a%2Cc%29%2C%28c%2Ce%29%7D%E5%91%A2%2C%E5%9B%A0%E4%B8%BA%28a%2Cb%29%28b%2Cc%29%E5%8F%AF%E4%BB%A5%E5%BE%97%E5%88%B0%28a%2Cc%29%28c%2Cd%29%28d%2Ce%29%E5%8F%AF%E4%BB%A5%E5%BE%97%E5%88%B0%28c%2Ce%29%E5%95%8A.)
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