作业帮求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/06 04:25:48
x){83OCӓ
,lm (n`20jyڰiu@`TO0ıO?o 7V@DS d.o0_X ( 6l6D X lSv.TY4 pV.HP&R]G 7҂5
< (1/.H̳ N
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值
求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
原式=sin(-1200+360*4)*cos(1230-360*3)+cos(-1020+3*360)*-sin(
-1050+360*3)
=sin(240)*cos(150)+cos(60)*sin(30)
=[-sin(60)]*[-cos(30)]+cos(60)*sin(30)
=-(√3）/2*-(√3)/2+1/2*1/2
=1
求sin(-1200°）×cos1290°+cos9-1020°)×sin（-1500°）+tan945°
求sin(-1200°）×cos1290°+cos9-1020°)×sin（-1500°）+tan95°
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855°
sin(-1200°)cos1290°+cos(-1020°）sin（-1050°)+tan855求值..
求音乐：sin( 1200度)cos1290度 cos( 1020度)in( 1050度)+tan495度
求sin(―1200°)·cos1290°+cos(―1020°)·sin(―1050°)+tan945°的值．
求sin﹙-1200°﹚·cos1290+cos﹙-1020°﹚·sin﹙-1050°﹚+tan945°的值
sin(-330°)怎么求?
求sin²10°+sin²20°+sin²40°+sin²50°+sin²70°+sin²80°
求sin平方10°+sin平方20°+.+sin平方80°的值
求sin²1°+sin²2°+sin²3°……sin²89°=?
求sin（-1050°）三角函数值
sin(-390°)求三角函数值
求值：sin(-1920°)=求过程
sin(-210°)求详细步骤
求大神求sin
Sin(15°+x)－sin(15°-x) 求大神!Sin(15°+x)－sin(15°-x)求大神!