作业帮求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 03:24:19
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求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值
求解求解吖~~~~
求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
原式=sin(-1200+360*4)*cos(1230-360*3)+cos(-1020+3*360)*-sin(
-1050+360*3)
=sin(240)*cos(150)+cos(60)*sin(30)
=[-sin(60)]*[-cos(30)]+cos(60)*sin(30)
=-(√3）/2*-(√3)/2+1/2*1/2
=1
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求sin(-1200°)×cos1290°+cos(-1020°)×sin(-1050°)的值求解求解吖~~~~
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