[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25求这道式子的值.
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[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25求这道式子的值.
[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25
求这道式子的值.
[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25求这道式子的值.
[(xy+2)(xy-2)-2x^2y^2+4]/(xy)
=[(x^2y^2-4)-2x^2y^2+4]/(xy)
=-x^2y^2/xy
=-xy
=-10*(-1/25)
=2/5
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